Beweise, dass in einer Gruppe von acht Leuten (mindestens) zwei am gleichen Wochentag Geburtstag haben.
Solution
´A = "Personen"´ ´B = "Wochentage"´
´f: A -> B´
´#A = 8´ ´#B = 7´
´#f^(-1)(b) >= |~ (#A)/(#B)
| >= |8/7 ~| >= 2´
- URL:
- Language: Deutsch
- Subjects: math
- Type: Proof
- Duration: 15min
- Credits: 1
- Difficulty: 0.3
- Tags: proof pigeonhole principle
- Note:
HPI, Mathematik I - Diskrete Strukturen und Logik, WS 2012/2013 - Created By: ad-si
- Created At:
2013-04-12 16:49:14 UTC - Last Modified:
2014-07-21 09:00:40 UTC